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iOS 之 Safari Or Web URL跳转到APP指定页面
有时候需要从文章中分享一个链接直接跳到APP的指定页面，这个怎么做呢?
其实很简单；只要是iphone自带的浏览器，都会自带一个识别APP的URL Schemes的功能，所以只要是特定的URL，都能被web识别，所以不管是在项目内部还是在Safari中，都可以实现URL跳转到指定页面的需求、
只要是符合特定格式的URL，都会跳入指定的APP中，然后再加上一些参数，即可实现从APP中跳入指定的页面
注：如果是其他APP内部的web页面，则不会进入跳转；那么有一个办法是引导用户分享到Safari去，然后再触发URL Schemes跳转
我的格式为："url schemes"://"Bundle id"/mod="viewContrllerID"?id="params"
比如testUrlSchemes://com.testBundleID.YH/mod=appstore?id="params"
这种方式还可以做更多的事，比如用作Route等等；这里只是做一个简述，更多精彩等大家去实现！！！
步骤如下：
首先进入APP是会进入这个回调方法中的：
- (BOOL)application:(UIApplication *)application openURL:(NSURL *)url sourceApplication:(NSString *)sourceApplication annotation:(id)annotation
{
BOOL ret = [ExtensionHandle handleOpenURL:url];
if (ret) {
return ret;
}else{
//handle other share URL
}
}
接下来在ExtensionHandle 的 handleOpenURL:中处理改URL及参数；
#define URL_SCHEME_PREFIX @"URL Schemes://" //这个是 URL Schemes
+ (BOOL)handleOpenURL:(NSURL *)url{
BOOL ret = [url.absoluteString hasPrefix:URL_SCHEME_PREFIX];
if (ret) {
NSString *bundelID = [[[NSBundle mainBundle] bundleIdentifier] lowercaseString];
if ([[url.absoluteString lowercaseString] rangeOfString:bundelID].location!=NSNotFound) {
NSArray *urlComponents = [url.absoluteString componentsSeparatedByString:[NSString stringWithFormat:@"%@/",bundelID]];
NSString *query = urlComponents.lastObject;
/*analyze params*/
NSDictionary *params = [self analyzeQuery:query];
if ([params[@"mod"] length] != 0) {
NSString *modStr = params[@"mod"];
if (url.query) {
modStr = [modStr stringByAppendingString:url.query];
}
[PageTransferHelper appJumpToPageWithModString:modStr];
}
}
}
return ret;
}
然后是解析参数出来，其实就是对字符串处理，分离处后面的参数
+(NSDictionary *)analyzeQuery:(NSString *)query
{
NSMutableDictionary *keyValues = [NSMutableDictionary dictionary];
NSArray *queryArray = [query componentsSeparatedByString:@"&"];
for (NSString *oneParma in queryArray) {
NSArray *keyValue = [oneParma componentsSeparatedByString:@"="];
if (keyValue.count >=2) {
keyValues[keyValue[0]] = keyValue[1];
}
}
return keyValues;
}
然后在PageTransferHelper的appJumpToPageWithModString:方法中处理界面跳转；
首先是处理参数中要跳转的类以及参数分离；
注：讲道理，string == appstore?id="params"
+ (void)appJumpToPageWithModString:(NSString *)string{
if (string.length==0) {
return;
}
/*URL 解码*/
string = [string stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSArray* paragamArr = [string componentsSeparatedByString:@"?id="];
classKey = [paragamArr firstObject];
//handle params
id obj = params;
NSInteger type;
NSDictionary *dict = [self pageTransferStringDict];
for (NSNumber *key in [dict allKeys]) {
if ([dict[key] isEqualToString:classKey]) {
type = [key integerValue];
break;
}
}
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(1.5 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
[self appJumpToPage:type andParagam:obj];
});
}
这里配置要跳转的界面
+ (NSDictionary*)pageTransferStringDict
{
return @{@(ePageTransferTypeAppStore):@"appstore"};
}
+ (NSDictionary*)pageTransferClassDict
{
return @{@(ePageTransferTypeAppStore):[AppStoreViewController class]};
}
接下来是处理真正的跳转界面以及传参数
注：type == ePageTransferTypeAppStore;
obj == "params";
+ (void)appJumpToPage:(NSInteger)type andParagam:(id)obj,...{
[AppDelegate dismissAllViewController];
AppDelegate *appDelegate = (AppDelegate *)[[UIApplication sharedApplication] delegate];
Class class = [self pageTransferClassDict][@(type)];
[appDelegate.rootViewController setSelectedIndex:0];
UIViewController *viewController = [[class alloc]init];
viewController.params = obj;
[appDelegate.rootViewController.navigationController pushViewController:viewController animated:NO];
}
在web中点击URL之后的回调是：
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType;
接下来的解析URL跟上面一样
